-16t^2+88t-72=0

Solution for -16t^2+88t-72=0 equation:

-16t^2+88t-72=0

a = -16; b = 88; c = -72;
Δ = b2-4ac
Δ = 882-4·(-16)·(-72)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-56}{2*-16}=\frac{-144}{-32}
=4+1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+56}{2*-16}=\frac{-32}{-32}
=1
$